@tipsywisdom

you are right and thank you for sharing the experience. I myself use semafor and cg.
Just saying this maybe the reason of your problem.

Define an array like Indicator_Value[2,61], then go through this array with loop, quite easy.

@tipsywisdom

you are right and thank you for sharing the experience. I myself use semafor and cg.
Just saying this maybe the reason of your problem.

@mmbinvest
I think the reason is that this indicator repaints.
And your EA records the arrows when they appear and plots the corresponding arrow on the chart.
When the indicator arrows repaint aka disappear, the EA's arrow don't move.

You know what? this indicator is tooo perfect, this is a sign of repainting like ZZ and tons of them.

Set it to 1 and try again?

If not, set both to 1 and try again?

Thank you for confirmation bro!

Please help me with a new question in detail:

What happens if:

1. I run the EA built with fxdreema on M5 chart.
2. under "on tick", I connect some blocks under "once per bar". The blocks under this "once per bar" is for example trend-filter-from-higher-time-frame (time frame all set to M30). The purpose is to save some computing resource, I use signal by closed candle (e.g. candel ID always 1) anyway.
3. I set the "time frame" of this "once per bar" as M30.

So what happens when the EA is activated?

• it goes through the current M30 bar once (after some ticks maybe), so I will get the right trend from higher-time-frame. Right?
• the next execution is then somewhere in the next M30-bar? So the blocks under this "once per trade" are executed some every 30 minutes EXEPT the first round. Right?

@jstap
Thank you!

That is loud and clear answer!

@l-andorrà

Thank you!

It is about execute of block #3, if the input of #3 are connected to 2x outputs.

dear friends,

please kindly answer one basic question which I could not found a clear clarification anywhere. Thank you!

is the same as:

OR

?

e.g. block #3 will be executed when both #1 && #2 are true, OR #1 || #2 is true? If simply connected without a "controlling block"

Thank you sir!