Topics created by khalids222

I guess the value for buy was not 21010 after it raised up again, because the value is calculated continous on candleID 0 and 1. I think you could see that on chart on the Trace buy value?

Maybe you could add a variable to save price level of last buy/sell trade, then make a second rule to open a new trade if the price retrace to that level again?

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0_1585330015671_69dfff27-5b8f-4f71-beca-d2ae83846733-image.png

Are you trying to create a hedging system? Not sure if that is what you're looking for.

@miro1360 THANK YOU VERY MUCH

"Applied price" does not mean any price value, dont use it like that.

Applied price refers to different parts of the candle: open, high, low, close, as you can see from the drop-down.

@josecortesllobat said in How can I know the price now?Is there an error?:

Candle 0 does not have Close price because is still being formed. Close price (0) depends on the Ask/Bid (Mid) price and changes while the the price moves. For that reason, those specific blocks were developed on fxDreema. They look for crosses between the price and an indicator.

Ok, thank you for the clarification.

@khalids222 Wish you the best in your ea

@trader-philipps said in How can I work on a candle (H1) & make the expert through one per bar:

No. The on Timer tab you only need if you want things to happen independent from any tick. Unfortunately all you do on on Timer tab you won't be able to test in back-test mode. So if there's nothing you want to do outside the market hours, you'd better go with the on Tick tab.

thank you very much

@trader-philipps said in One volumes constant in all cases:

In that case just specify a fixed lot size on Buy and Sell blocks. use a constant if you want to make it adjustable from the EA's parameters.

Thank you very much, your solutions and advice are always of my interest

@roar said in How can I add a specific level to the moving average at fxdreema ?:

@khalids222 You want to check if candle crosses 10-MA?
Don't use candle body size, or candle total size.
Those are sizes, not levels.

If you want to take action when a candle touches moving average, a solution is to use two conditions:

if candle open > MA, then
if candle close < MA
-> take action

another case:
if candle open < MA, then
if candle close > MA
-> take action

Just for my interest, doesn't do x> or x< do the same? If you compare on candle cross per candle, you'd probably miss crosses with gaps. For instance candle ID2 close was below MA and candle ID 1 open was above.

@trader-philipps
Thank you very much for the help. Your solutions are always great
I appreciate you help me

@titangeorge
Thank you very much, I will try it.

@l-andorrà THANK YOU

@roar THANK YOU VERY MUCH

On your first issue, you should put this block ABOVE blocks 216 and 217 at the sam time.

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Additionally, you will need a time period for this block to be unchecked. I would recommens a variable to do it.

On your second issue, you are looking for the holy grial! Not sure what to recommend, honestly. Maybe decreasing your money target?

@trader-philipps
yes, Thank you very much for your cooperation, it is working well now
0_1579495277525_yes.jpg

@trader-philipps
0_1579462773722_close path.jpg
Here there are several buys and several sells on the same path, I tried to close the path after the first buy or sale. but It did not work
Is there a way before opening a new deal, checking the previous deal, if the new deal is the same as the old one, bypasses.
And if the matter is different, it opens in reverse؟

https://fxdreema.com/shared/Ua0mk1Cfc

@trader-philipps This is exactly required - thanks to everyone and especially @trader-philipps Thank you for your effort - you are always creative

@trader-philipps said in How can I collect the latest open positions in the event of a trend change?:

So after having a deep thought about it, the algorythm seems to be MathAbs(buylots-selllots)+lots. MathAbs calculates the absolute number, which means 1 and -1 have the absolute number value of 1.
Right?

Yes, it is true there are two methods: The first is to use the absolute value. This is easier and sufficient.
The second method: squaring the number and then putting the root in it, thus eliminating the negative.

I think the first is easier

The problem has been resolved. Thank you everyone

@roar thank you very much